Question

In ΔPQR ∠Q=90°, PQ=12 cm, QR=5cm. Find the circum radius of ΔPQR.​

Answer 1

Answer:

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Answer 2

Answer:

According to Pythagoras theoram,

PQ^2+QR^2=PR^2.

12^2+5^2=PR^2.

144+25=169

PR^2=169

PR=√169

PR=13cm.

13cm Is the Diameter(hypotenuse)

So,Radius=13÷2

=6.5

Trick:According to Pythagorean triplets we can find hypotenuse quickly(5,12,13)

Step-by-step explanation:

Circum radius=6.5

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