In ΔPQR, ∠Q=90°, PQ=QR. Find ∠P
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IN TRIANGLE PQR,
ANGLE Q = 90 DEGREES
ANGLE P AND R ARE EQUAL BCOZ THE TWO SIDES PQ AND QR ARE EQUAL
THEN.......
180 - 2 ANGLE P = 90
2 ANGLE P = 90
ANGLE P = 45 DEGREES......
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Answer:
here angle Q=90
PQ=QR
From property of isosceles triangle
opposite angles are congruent due to congruent sides .
opp. angle of PQ=angle R
Opp.angle of QR=angle angle P
let angle P and R are x
angle P+Q+R=180........(property of traingle)
x+90+x=180
2x=180
x=90
Therefore,
angle P=90
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