Question

in ∆ pqr, right angled at q, angle p is four times as large as angle r, find angle p and angle r​

Answer 1

Answer:

let p=4x

r=x

4x+x+90=180(asp)

5x=180-90=90

x=90/5=45

p=4x=4×45=180

r=x=45

hence proved

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Answer 2

Given :- Angle PQR = 90
Angle P is four time as
compared to angle R


Let the angle R be x

If angle R = x , then angle P = 4x [Given]

4x+x+90 = 180 [Angle Sum Property]

5x+90 = 180

5x = 180-90

5x = 90

x = 90/5

[b]x = 18[/b]

Angle R = x = 18
Angle P = 4x = 4*18 = 72





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