Question

In ∆ PQR, right angled at Q, PQ= 3 cm and PR= 6 cm. Determine <QPR and < PRQ​

Answer 1

Answer:

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Answer 2

Answer:

Given, right angled at Q

          PQ = 3 cm

          PR = 6 cm

sin R = side of opp. angle R / Hypotenuse

sin R = PQ/PR

sin R = 3 / 6

sin R = 1 / 2

sin R = sin 30 degree

so, <PRQ = 30 degree. ANS.

We know, <P + <Q + <R = 180 degree

<P = 90 + 30 = 180 degree

<P = 60 degree.

So, <QPR = 60 degree ANS.

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