Question

In ΔPQR, right-angled at Q, PQ = 3cm and PR = 6cm, find sin R.

Answer 1

Answer:

1/2 is the answer..

..

..

..

Answer 2

Answer:

✌ PLEASE MARK ME BRAINLIST ✌

Step-by-step explanation:

Answer

In ΔPQR; LQ=90 o

PQ=3cm; PR=6cm

QR= √6 2 −3 2 =3 √3

sin(LQPR)= PR

QR

= 3√3 √3

6 2

So, LQPR=60 o ⇒ LQRP=30 o .