Question

In ΔPQR, right angled at Q, PQ = 4 cm and RQ = 3 cm. Find the values of sin P, sin R, sec P and sec R.

Answer 1

in ∆PQR,
By Pythagoras theorem
H² = P² + B²
PR² = PQ² + QR²
PR² = 4² + 3²
PR = $\sqrt{16 + 9}$
PR = 5cm

sin(p) = $\frac{qr}{pr}$
= $\frac{3}{5}$

sin(R) = $\frac{pq}{pr}$
= $\frac{4}{5}$

sec (P) = $\frac{pr}{pq}$
= $\frac{5}{4}$

sec R = $\frac{pr}{qr}$
= $\frac{5}{3}$