In ∆PQR right angled at Q , PR=29 cm ,PQ= 20cm then find tan P – cot R.
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Solution :
In ΔPQR, ∠Q = 90°.
By Pythagoras theorem,
PR² = PQ² + QR²
QR² = PR² - PQ²
QR² = (29)² - (20)²
QR² = 841 - 400
QR = √441
QR = 21 cm
tan P= side opposite to ∠P/side adjacent to ∠P
= QR/PQ
= 21/20
cot R = Side adjacent to ∠R/side opposite to ∠R
= QR/PQ
= 21/20
Hence,
= tan P - cot R
= 21/20 - 21/20
= 0
∴ Value of tan P - cot R is 0
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