Question

In ∆PQR right angled at Q , PR=29 cm ,PQ= 20cm then find tan P – cot R. ​

Answer 1

Solution :

In ΔPQR, ∠Q = 90°.

By Pythagoras theorem,

PR² = PQ² + QR²

QR² = PR² - PQ²

QR² = (29)² - (20)²

QR² = 841 - 400

QR = √441

QR = 21 cm

tan P= side opposite to ∠P/side adjacent to ∠P

= QR/PQ

= 21/20

cot R = Side adjacent to ∠R/side opposite to ∠R

= QR/PQ

= 21/20

Hence,

= tan P - cot R

= 21/20 - 21/20

= 0

∴ Value of tan P - cot R is 0

Answer 2

Answer:

it is answerd already

Step-by-step explanation:

follow me