Math, asked by StudentSaif, 7 months ago

In ∆PQR, right angled at Q,PR =5√5cm,PQ =10cm, then tanP =

Answers

Answered by abc1002

1

Answer:

1/2

Step-by-step explanation:

By Pythagoras theorem,

H²=P²+B²

(5 root 5)²= (10)²+QR²

125= 100+QR²

QR²=25

QR=5 cm

Now, Tan P= Perpendicular/Base

Tan P= 5/10= 1/2

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