Question

In ∆PQR, right angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values of sinP , cosP and tanp​

Answer 1

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Answer 2

Answer:

hey mate here is your answer....

Explanation:

➡️ Given that PR + QR = 25 and PQ= 5

➡️ Let PR be x, QR= 25 - x

➡️ By Pythagoras theorem,

• PR² = PQ² + QR²
• x² = (5)² + (25-x)²
• x² = 25 + 625 + x² - 50x
• 50x = 650
• x = 13
• PR = 13cm

➡️ QR = ( 25 - 13 ) = 12

▶️ sinP = QR / PR = 12 / 13

▶️ cosP = PQ / PR = 5 / 13

▶️ tanP = QR / PQ = 12 / 5

Hope it helps!✌️