Question

In ∆PQR, right angled at Q,PR+QR=25cm and PQ=5cm . Determine the value of sin P,Cos P and tan P .​

Answer 1

Step-by-step explanation:

PR+QR=25

PR=25-QR

using Pythagoras theorem

(PR)²=(PQ)²+(QR)²

(25-QR)²=(5)²+(QR)²

625+QR²-50QR=25+QR²

600=50QR

QR=12

PR =25-12

PR=13

sinP=P/H

sinP=12/13

cosP=B/H

cosP=5/13

tanP=P/B

tanP=12/5

Answer 2

Answer:

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