Question

In ΔPQR, right-angled at Q, QR = 4 cmcm and PR = 5 cm.Find the value of cos P-cot R​

Answer 1

P²=H²- B²

P=√(5)²- (4)²

P=√25-16

P=9

THAN

COS P= 3/5

COT P= 4/3

NOW

Cos P - Cot R

3/5-4/5 = 9-20/15

= -11/15

Answer 2

Step-by-step explanation:

PQ=5cm

⇒PR+QR=25cm

⇒PR=25−QR

Now, In △PQR

⇒(PR)

2

=PQ

2

+QR

2

⇒(25−QR)

2

=5

2

+QR

2

⇒625+QR

2

−50QR=25+QR

2

⇒50QR=600

⇒QR=12cm

⇒PR=25−12=13cm

∴sinP=

PR

QR

=

13

12

,cosP=

PR

PQ

=

13

5

,tanP=

PQ

QR

=

5

12

Hence, the answers are sinP=

13

12

,cosP=

13

5

,tanP=

5

12

.