In ΔPQR, right-angled at Q (see Fig. 8.20), PQ = 3 cm and PR = 6 cm. Determine ∠QPR and ∠PRQ.
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2
PR^2=PQ^2 × QR^2
36. = 9. × QR^2
QR^2= 36/9
= 4cm
36. = 9. × QR^2
QR^2= 36/9
= 4cm
Answered by
7
So Angle QPR = 60 degree
Angle PRQ = 30 degree
Angle PRQ = 30 degree
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