In ∆PQR seg PS side QR .T is the mid-point of side QR.
PQ = 17cm, PR = 10cm, SR = 6cm
Find QT.
(Use Pythagoras theorem)
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Step-by-step explanation:
PQ2+PR2=2(PS2+SR2)
172+112=2(132+SR2)
289+121=2(169+SR2)
410=2(169+SR2)
(169+SR2)=205
SR2=36
SR=6 cm
Since S is the midpoint of QR
QR=2×SR
QR=12
QR=12 cm.
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