Question

In ∆ PQR, seg RS bisect ,if PR=15,RQ=20,PS=12,then SQ=?​

Answer 1

Answer:

sq=16

Explanation:

PR/QR=PS/SQ.....(ANGLE BISECTOR THEOREM)

15/20=12/SQ

20*12/15=SQ

16=SQ

Answer 2

As we know Interior angle Bisector Theorem,

In the triangle PQR, the angle bisector intersects the side PQ with point S.$\frac{PS}{SQ}=\frac{PR}{RQ}$

Given: PR=15, RQ=20, PS=12, then SQ=?​

Using Interior angle Bisector Theorem,

$\frac{PS}{SQ}=\frac{PR}{RQ}$

$\frac{12}{SQ}=\frac{15}{20}$

$\frac{12}{SQ}=\frac{3}{4}$

$SQ=\frac{48}{3}$

$SQ=16$

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