Question

in ∆PQR such that angle Q=30° , angle R=60° find angle P​

Answer 1

Answer:

P =90

Angle sum property of triangle =

sum of it's all angles = 180°

Q + R + P = 180°

30°+60°+P = 180°

90°+P= 180°

P =180°- 90°

P = 90°