Question

In ∆ PQR , the angle bisector of the angle PQR and angle PRQ meet at O. If angle QPR =80° then find angle QPR.
Pls tell me the answer fastly
Thanku

Answer 1

Step-by-step explanation:

In ΔPQR

∠P+∠Q+∠R=180° (Angle sum property of a triangle)

Since ∠P= 80°

∠Q+∠R=100°

In ΔOQR

∠O+∠Q/2+∠R/2=180° (Angle sum property of a triangle)

⇒∠O+(∠Q+∠R)/2 =180°

=>∠O+50=180°

⇒∠O=130°

There seems to be a mistake in this question. The correct question is to find ∠QOR. This is what I have solved here.

Regards :)

Answer 2

If angle QPR=80°,

Then, angle QPR=80°{GIVEN}

Such a big mistake