Question

in Δpqr the bisector of angle pqr and angle prq intersect each other at o. prove that angle qor=90° + 1/2 angle p​

Answer 1

Step-by-step explanation:

p+q+r=180°

2oqr+2orp=180°-p

2(oqr+orp)=180°-p

oqr+orp=90°-p/2 -----------(1)

In triangle QOR,

oqp+orq+qor=180°

oqr+orq=180°-qor ----------(2)

from eq. (1) and (2)

90°-p/2=180°-qor

qor=180°-90°+p/2

qor=90°+p/2

(Hence proved)