Question

In pqr, triangle q =90 degree and pq square + qr square = then find length hypo tenuous pr​

Answer 1

Step-by-step explanation:

This is converse of Pythagoras theorem

We can prove this contradiction sum q2=p2+r2 in ΔPQR while triangle is not a rightangle

Now consider another triangle ΔABC we construct ΔABC AB=qCB=b and C is a Right angle

By the Pythagorean theorem (AC)2=p2+r2

But we know p2+r2=q2 and q=PR 

So (AB)2=p2+r2=(SR)2

Since PQ and AB are length of sides we can take positive square roots

AC=PQ

All the these sides ΔABC are congruent to ΔPQR 

So they are congruent by sss theorem