Question

In production of sulphur trioxide,100 kmol of sulphur dioxide and 200 kmol

of oxygen are fed to reactor.Product stream contains 80 kmol sulphur

trioxide.Find % conversion of sulphur dioxide.
​

Answer 1

Step-by-step explanation:

Given In production of sulphur trioxide, 100 kmol of sulphur dioxide and 200 kmol  of oxygen are fed to reactor.Product stream contains 80 kmol sulphur  trioxide.Find % conversion of sulphur dioxide.

• ​The sulphur dioxide required to be reacted is 1 k mol,  
• So SO 2 + ½ O2 -- SO 3
• 1 k mol of SO2 is equal to 1 k mol of SO3
• Therefore 80 k mol of SO3 requires will be 80 x 1 / 1
•                                                                    = 80 k mol
• Now percentage conversion of SO2 will be  
• kmol SO2 that is reacted / kmol SO2 charged x 100
•                 = 80 / 100 x 100
•                 = 80

Reference link will be

https://brainly.in/question/25769841

Answer 2

Answer:

80is the final answer hope it helps you