In progression a,d,sn are given then find n and an
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Put the given values in the equation.
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Let n=N
N =
{(d-2a)+-√(4a^2+d^2-4ad+8dSn)}/2d
An=a+(N-1)d
or. An=2Sn/N-a
N =
{(d-2a)+-√(4a^2+d^2-4ad+8dSn)}/2d
An=a+(N-1)d
or. An=2Sn/N-a
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