Question

In projectile motion, the total flight time is _______.
A) equal to the time required to reach the maximum height B) thrice the time required to reach the maximum height C) four times the time required to reach the maximum height D) twice the time required to reach the maximum height

Answer 1

Answer:

4 times necessary to reach max hieght

Answer 2

In projectile motion, the total flight time is twice the time required to reach the maximum height. (option D)

• The projectile motion can be defined as the motion which is experienced by an object or a body that is thrown or projected obliquely nearby the earth's surface. In such a motion, the object moves along a curved path under the acceleration due to gravity.
• For a projectile motion, the time required by the object to reach maximum height is given by the relation $t_h=\frac{u \cdot \sin \theta}{g}$. On the other hand, the relation that gives the time of flight is $T=\frac{2 \cdot u \cdot \sin \theta}{g}$. Where u = magnitude of the velocity of the object, θ = projectile angle, and g = acceleration due to gravity.
• Therefore, from the above relations, it can be clearly seen that $T=2 t_h$.