Question

In pure water at 298 k, the electrode potential of h-electrode will be

Answer 1

Answer:

Electrode Potential(Nerst Equation) -



- wherein



 is concentration of species

F= 96487 C 

R= 8.314 

T= Temperature in kelvin

 

 P(H)=7 for water 

-log(H+)=7

(H+)=10-7





 

Answer 2

Answer:

The pressure of H2 required to make the potential of H2 -electrode zero in pure water at 298 K is: 10-¹⁴

Explanation:

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