Question

in PYTHON read a number and display its sum of factors. (write the program)

Answer 1

Explanation:

def divSum(n) :

      

    # Final result of summation 

    # of divisors

    result = 0

    

    # find all divisors which

    # divides 'num'

    for i in range(2,(int)(math.sqrt(n))+1) :

  

        # if 'i' is divisor of 'n'

        if (n % i == 0) :

  

            # if both divisors are same 

            # then add it only once

            # else add both

            if (i == (n/i)) :

                result = result + i

            else :

                result = result + (i + n//i)

          

          

    # Add 1 and n to result as above 

    # loop considers proper divisors

    # greater than 1.

    return (result + n + 1)

    

# Driver program to run the case

n = 30

print(divSum(n))

Output: 72