IN Qadrilateral ABCD,angle A= 90angls B=60 angle C=50 find D
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Since the sum of all the angles of quadrilateral is 360°.
A+B+C+D=360°
90°+60°+50°+D=360°
200°+D=360°
D=160°
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Given
Angel A=90°
Angel B=60°
Angel C=50°
Angel D= ?
In quadrilateral ABCD,
Angel DAB + angle ABC + Angle BCD + Angel CDA=360^
90° + 60° + 50° + angle CDA = 360°
Angel CDA = 360° - 200°
Angel CDA=160°
. `. angle D =160°
Angel A=90°
Angel B=60°
Angel C=50°
Angel D= ?
In quadrilateral ABCD,
Angel DAB + angle ABC + Angle BCD + Angel CDA=360^
90° + 60° + 50° + angle CDA = 360°
Angel CDA = 360° - 200°
Angel CDA=160°
. `. angle D =160°
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