Question

In quad.ABCD,B=90°,AD^2=AB^2+BC^2+CD^2,prove that ADC=90°​

Answer 1

Step-by-step explanation:

just check it I think ur question is incorrect prove should be given to do <ACD =90°

if it is so ......

then,

in triangle ABC

AC^2=AB^2+BC^2

HENCE IN TRIANGLE

ADC

AD^2= AC^2 +CD^2

BY CONVERSE PYTHAGORAS THEOREM

ANGLE C =90° PROVED

hope this will help