in quad. PQRS, PQllSR, angle RPQ = x", angle
RPS = y", angle PSR=2" also x= 3 /5 y, y= 5/7z,
then value of x,y,z
respectively is
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qquad m \angle QPSm∠QPSm, angle, Q, P, S is a straight angle.
\qquad m \angle QPR = 7x - 4^\circm∠QPR=7x−4
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m, angle, Q, P, R, equals, 7, x, minus, 4, degrees
\qquad m \angle RPS = 9x - 40^\circm∠RPS=9x−40
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m, angle, R, P, S, equals, 9, x, minus, 40, degrees
Find m\angle QPRm∠QPRm, angle, Q, P, R:
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