Question

In quadateral ABCD, Angle A=(2x+4) Angle B=(Y+3) Angle C=(2Y+10) and Angle D= (4X-5), Find Angle A,B,C,D

Answer 1

THE ANSWER MAY BE WRONG IF YOU WILL GIVE ME THE FIGURE THEY I CAN GIVE YOU A CORRECT SOLUTION
2x+4=2y+10......(i)
y+3=4x-5.....(ii)
in (i),2x-2y=6
x-y=3
x=3+y
In (ii),
3+5=4x-y
8=4(3+y)-y
8=12+4y-y
-4=3y
y=-4/3
In (i),2x+4=2y+10
2x-2y=6
x-y=3
x+4/3=3
x=3-4/3
x=5/3
Therefore,∠A=2x+4=2 x 5/3+4
=10/3+4
=22/3°
Again,∠D=4x-5=4 x 5/3-5
=20/3-5
=5/3°
Again,∠C=2y+10=2x -4/3 +10
=-8/3+10
=22/3°
Again,∠B=y+3
-8/3+3
=1/3°