in quadilateral ABCD b= d=90° prove that AB²-AD²=CD²-CB²
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ABCD is quadilatral
for triangle ADC
AD^2+DC^2=AC^2===============(1)
because ADC is right angle triangle
again for triangle ABC
AB^2+BC^2=AC^2==============(2)
now equation (1) and (2)
AD^2+DC^2=AB^2+BC^2
AB^2-AD^2=CD^2-BC^2
hence proved
for triangle ADC
AD^2+DC^2=AC^2===============(1)
because ADC is right angle triangle
again for triangle ABC
AB^2+BC^2=AC^2==============(2)
now equation (1) and (2)
AD^2+DC^2=AB^2+BC^2
AB^2-AD^2=CD^2-BC^2
hence proved
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