in quadratic equation kx^2 - 6 x-1=0determine the value of k for which equation does not have any real root
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therefore the value of 'k' is -5
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pavithra6999:
Wrong answer
K=-9
sorry
calculated wrong
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Heya
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For complex / No real roots Descrimnant <0
Descrimnant of given quadratic equation is = 36 - 4 ( k ) × ( -1 )
=>
36 + 4k <0
=>
4k < 36
=>
k < 9
So, The possible values of k are ( -infinity to 9 )
_______________________________
For complex / No real roots Descrimnant <0
Descrimnant of given quadratic equation is = 36 - 4 ( k ) × ( -1 )
=>
36 + 4k <0
=>
4k < 36
=>
k < 9
So, The possible values of k are ( -infinity to 9 )
it has no roots
No, Dear it has two roots but both are complex
read the question carefully
Dear, put any value of k which is less than 9 and then solve the quadratic equation you will get two values of i,e two roots which both are complex/No real roots
*two vlaues of k
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