Math, asked by TanBRAIN, 9 months ago


In quadrilateral ABCD, AB = 10 cm, BC = 6 cm,
CD = 2.8 cm, DA = 6 cm and its diagonals are 8 cm each.
(i) Are angle ADB and ACB right angles?
(ii) Is ABCD a trapezium? If yes, find its height.
(iii) Find the area of the quadrilateral.​

Answers

Answered by techtro
24

Answer: The answers are as follows:

•The given shape is a isosceles trapezoid as it has two equal sides and rest two are unequal and the diagonals are equal.

i) None of the angles are right angle in a isosceles trapezoid.

ii) ABCD is not a trapezium as it has two parallel sides since it is a isosceles trapezoid. Its height is 4.8cm.

( you can construct a right angle triangle at one end of the trapezoid and the using Pythagoras theorem in that right angle triangle with Hypotenuse=6cm and Base=3.6cm {since (10-2.8)/2= 3.6}

iii) Area of a quadilateral = basexheight

=10x4.8 cm sq=48 cm sq.

Similar questions