In quadrilateral ABCD, AB = 10 cm, BC = 6 cm,
CD = 2.8 cm, DA = 6 cm and its diagonals are 8 cm each.
(i) Are angle ADB and ACB right angles?
(ii) Is ABCD a trapezium? If yes, find its height.
(iii) Find the area of the quadrilateral.
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Answer: The answers are as follows:
•The given shape is a isosceles trapezoid as it has two equal sides and rest two are unequal and the diagonals are equal.
i) None of the angles are right angle in a isosceles trapezoid.
ii) ABCD is not a trapezium as it has two parallel sides since it is a isosceles trapezoid. Its height is 4.8cm.
( you can construct a right angle triangle at one end of the trapezoid and the using Pythagoras theorem in that right angle triangle with Hypotenuse=6cm and Base=3.6cm {since (10-2.8)/2= 3.6}
iii) Area of a quadilateral = basexheight
=10x4.8 cm sq=48 cm sq.
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