Question

In quadrilateral ABCD AB is the shortest side and CD is the longest side show that <A> <C​

Answer 1

$\huge \red{hello \: mate}$

In ∆ABC,

AB<BC-----(AB is the shortest side)

Since, the angle opposite to smaller side will be lesser

Angle 2<Angle 1------(1)

In ∆ADC,

AD<CD(CD is the longest side of the quadrilateral)

The angles opposite the smaller side will be lesser,

Angle 4<Angle 3-------(2)

Adding (1) and (2),

∠1+∠3>∠2+∠3

∠A>∠C

Hence proved.