Question

In quadrilateral ABCD AB is the shortest side and CD is the longest side show that <A> <C​

Answer 1

${\underline{\underline{Answer~:}}}$

In ∆ABC,

In ∆ABC,AB<BC-----(AB is the shortest side)

In ∆ABC,AB<BC-----(AB is the shortest side)Since, the angle opposite to smaller side will be lesser

In ∆ABC,AB<BC-----(AB is the shortest side)Since, the angle opposite to smaller side will be lesserAngle 2<Angle 1------(1)

In ∆ABC,AB<BC-----(AB is the shortest side)Since, the angle opposite to smaller side will be lesserAngle 2<Angle 1------(1)In ∆ADC,

In ∆ABC,AB<BC-----(AB is the shortest side)Since, the angle opposite to smaller side will be lesserAngle 2<Angle 1------(1)In ∆ADC,AD<CD(CD is the longest side of the quadrilateral)

In ∆ABC,AB<BC-----(AB is the shortest side)Since, the angle opposite to smaller side will be lesserAngle 2<Angle 1------(1)In ∆ADC,AD<CD(CD is the longest side of the quadrilateral)The angles opposite the smaller side will be lesser,

In ∆ABC,AB<BC-----(AB is the shortest side)Since, the angle opposite to smaller side will be lesserAngle 2<Angle 1------(1)In ∆ADC,AD<CD(CD is the longest side of the quadrilateral)The angles opposite the smaller side will be lesser,Angle 4<Angle 3-------(2)

In ∆ABC,AB<BC-----(AB is the shortest side)Since, the angle opposite to smaller side will be lesserAngle 2<Angle 1------(1)In ∆ADC,AD<CD(CD is the longest side of the quadrilateral)The angles opposite the smaller side will be lesser,Angle 4<Angle 3-------(2)Adding (1) and (2),

In ∆ABC,AB<BC-----(AB is the shortest side)Since, the angle opposite to smaller side will be lesserAngle 2<Angle 1------(1)In ∆ADC,AD<CD(CD is the longest side of the quadrilateral)The angles opposite the smaller side will be lesser,Angle 4<Angle 3-------(2)Adding (1) and (2),∠1+∠3>∠2+∠3

In ∆ABC,AB<BC-----(AB is the shortest side)Since, the angle opposite to smaller side will be lesserAngle 2<Angle 1------(1)In ∆ADC,AD<CD(CD is the longest side of the quadrilateral)The angles opposite the smaller side will be lesser,Angle 4<Angle 3-------(2)Adding (1) and (2),∠1+∠3>∠2+∠3∠A>∠C

In ∆ABC,AB<BC-----(AB is the shortest side)Since, the angle opposite to smaller side will be lesserAngle 2<Angle 1------(1)In ∆ADC,AD<CD(CD is the longest side of the quadrilateral)The angles opposite the smaller side will be lesser,Angle 4<Angle 3-------(2)Adding (1) and (2),∠1+∠3>∠2+∠3∠A>∠CHence proved.

mark as brainiliest answer and plz follow me.

Answer 2

Step-by-step explanation:

What would you like to ask?

MATHS

In quadrilateral ABCD, AB is the longest side CD is the shortest side. Prove that ∠A>∠C.

ANSWER

In ΔADC,

DC<AD

∠2<∠4 (angles opposite to greater side is greater)

ΔABC,

AB>BC

∠3>∠1 (angles opposite to greater side is greater)

∴∠3+∠4>∠1+∠2

∠C>∠A

Hence, proved.

solution