Question

In quadrilateral ABCD AC= 16 cmBE= 4 cm . Find the area

Answer 1

the quadrilateral ABCD is divided into two triangles,
area of triangle ABC=1/2xbasexheight
area of ABC=1/2x16x4
area of ABC=32

Area of triangle ADC=1/2xbasexheight
Area of ADC=1/2x16x12
area of ADC=96

Area of quadrilateral ABCD = area of ABC+area of ADC
area of quadrilateral ABCD = 32+96
area of ABCD=128

Answer 2

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Answer:

Area of a common quadrilateral is given by the formula,                                  A = 1/2*common base of triangles*[height triangle 1  +  height of triangle 2]

NOTE : Common base of triangles = Main diagonal of the quadrilateral considered

Given data :-

For triangle ABC ,

Height = h1 =4cm

Common base , b =16cm

For triangle ADC ,

Height = h1 =12cm

Common base , b =16cm

Step-by-step explanation:

Area of the quadrilateral , A =b[h1+h2]/2

=> A = 16 [ 4 + 12 ]/2

=> A = 256/2

=> A = 128 square cm

Hence, Area of the given quadrilateral ABCD = 128 square cm.

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