Math, asked by divyaadivya357, 8 months ago

In quadrilateral ABCD AC = AD and AB Bisect A show that ∆ABC~∆ABD what you can say about BC and BD​

Answers

Answered by priyapriyanshi
13

Answer:

Proof : In triangle ABC and triangle ABD

AC = AD ( given )

angle A = angle A ( common side

AB bisect

angle A)

AB = AB ( common )

therefore ∆ABC congruent to ∆ ABD

by SAS criterion

hence, BC = BD ( CPCT )

Answered by MissAngry
3

Question :-

In quadrilateral ACBD, AC = AD and AB bisects ∠ A (see figure). Show that ∆ABC ≅ ∆ABD. What can you say about BC and BD?

Answer :-

In quadrilateral ACBD, we have AC = AD and AB being the bisector of ∠A.

Now, In ∆ABC and ∆ABD,

AC = AD (Given)

∠ CAB = ∠ DAB ( AB bisects ∠ CAB)

and AB = AB (Common)

∴ ∆ ABC ≅ ∆ABD (By SAS congruence axiom)

∴ BC = BD (By CPCT)

Plz mrk as brainliest ❤

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