Question

in quadrilateral abcd angle a is equal to 4 times angle c, angles b and d are equal to half of angle c then the measure of angle d is what?

Answer 1

Answer:

We are given ∠B+∠D=180

∘

. Using angle-sum property of a quadrilateral, we get

∠A+∠C=360

∘

−180

∘

=180

∘

.

Since ∠A and ∠C are of equal measure, we obtain ∠A=∠C=

2

180

∘

​

=

Explanation:

Sorry if it is wrong!<3

Answer 2

Here is ur answer mate  :-

let, angle C be 'x'

so, angle A would be '4x'

Also, angle D and B would be 1/2x and 1/2x respectively.

As we know, angle sum of a quadrilateral is 360°

So, we can obtain a equation the basis of angle sum property of a quadrilateral, i.e

x + 4x + 1/2x + 1/2x = 360°

5x + x = 360

6x = 360

x = 360÷6

x = 60°

Now, as x=60°

angle A = 4x = 240°

angle B = 1/2x = 30°

angle C = 60°

angle D = 1/2x = 30°

∴angle D  is 30°

Hence, we have found each angle of this quadrilateral ABCD

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