in quadrilateral ABCD angle C=64 angle D= angle C-8°, angle A=5 (a+2)° and angle B=2 (2a+7)° calculate angle A
Answers
Answered by
31
We know that sum of all angles of quad is 360
So
64 +(64-8)+5 (a+2)+2 (2a+7) = 360
64 + 56 + 5a + 10 + 4a +14 = 360
64 + 56 + 9a + 24 = 360
144+ 9 a = 360
9a = 360 - 144
a = 216/ 9
a = 24 Ans
So
64 +(64-8)+5 (a+2)+2 (2a+7) = 360
64 + 56 + 5a + 10 + 4a +14 = 360
64 + 56 + 9a + 24 = 360
144+ 9 a = 360
9a = 360 - 144
a = 216/ 9
a = 24 Ans
Answered by
8
Hlo mate here is ur ans.....
Pls refer to the attachment above.....
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