In quadrilateral abcd ao and do are the bisectors of angle a and angle
d. prove that angle aob=1/2(angle b+angle c)
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We know angle A+angle B +angle C+ angle D=360 (1)
In triangle ABO angle AOB+ 1/2(angle A+angle B)=180
2(AOB+ 1/2(angle A+angle B)=360 (2)
We have angle 2 AOB + angle A+ angle B = angle A + angle B +angle C+ angle D
This gives angle AOB= (angle C + angle D)/2
In triangle ABO angle AOB+ 1/2(angle A+angle B)=180
2(AOB+ 1/2(angle A+angle B)=360 (2)
We have angle 2 AOB + angle A+ angle B = angle A + angle B +angle C+ angle D
This gives angle AOB= (angle C + angle D)/2
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