In quadrilateral ABCD, AP and BP are bisectors of ∠A and ∠B respectively. Find the value of x, if D = 130º, ∠C = 60º.
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[tex]AP and BP are bisectors of two adjacent angles A and B of a quadrilateral ABCD.
We know that the sum of all the angles of a quadrilateral is 360°.
⇒∠A+∠B+∠C+∠D=360°, ∠A+∠B=360°−(∠D+∠C)
∴ In △PAB;
⇒∠APB+∠PAB+∠PBA=180° [ Angle sum property ]
⇒∠APB+21∠A+21∠B=180°
∴AP and BP are the bisectors of two adjacent angles A and B.
∴2∠APB+∠A+∠B=360°
⇒2∠APB=360°−(∠A+∠B)
∴2∠APB=∠C+∠D
⇒∠APB=2130o+60o=95°
∴x=95°.
Hence, the answer is 95°.
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