Question

. In quadrilateral ABCD, BC is the diagonal, DO is perpendicular to BC, and CX is perpendicula AB = 25 cm, BC = 16 cm, CX = 8 cm, and DO = 5 cm, find the area of the quadrilateral

Answer 1

Area of quadrilateral ABCD=140 square cm

Step-by-step explanation:

In quadrilateral ABCD

OD=5 cm

BC=16 cm

AB=25 cm

CX=8 cm

Area of triangle=$\frac{1}{2}\times base\times height$

By using the formula

Area of triangle BCD=$\frac{1}{2}\times BC\times OD=\frac{1}{2}\times 16\times 5=40cm^2$

Area of triangle ABC=$\frac{1}{2}\times AB\times CX$

Area of triangle ABC=$\frac{1}{2}\times 8\times 25=100cm^2$

Area of quadrilateral ABCD=Area of triangle BCD+area of triangle ABC

Area of quadrilateral ABCD=40+100=140 square cm

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https://brainly.in/question/14110359:Answered by Lublana

Answer 2

Answer:

140 cm²

Step-by-step explanation:

So,

let DO=5cm

BC=16 CM

AB=25 CM

CX=8 CM

So, area of ️ = 1/2*b*h

AREA OF ️ BCD= 1 /2 *BC*DO

= 1/2 *16*5

= 40cm².

AREA OF ️ ABC= 1/2 * AB* CX

= 1/2 * 25* 8

= 100CM².

So, area of quadrilateral ABCD= 40+100=140CM².(ans)