In quadrilateral ABCD, BC is the diagonal, DO is perpendicular to BC, and CX is perpendicular to AB.
AB = 25 cm, BC = 16 cm, CX = 8 cm, and DO = 5 cm, find the area of the quadrilateral.
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Answer:
Correct option is
A
square
ΔAOB,ΔAOD
DO=OD ( mid point )
AO=OA (common side)
∠AOB=∠AOD (right angle )
So ΔAOB,ΔAOD
So AB=AD
And ∠ABc=∠ADC=90
0
Similarly AB=BC=CD=AD can be proved that ABCD is a square
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