Question

In quadrilateral ABCD, BC is the diagonal, DO is perpendicular to BC, and CX is perpendicular to ABE
AB = 25 cm, BC = 16 cm, CX = 8 cm, and DO = 5 cm, find the area of the quadrilateral.​

Answer 1

BC=16 cm

AB=25 cm

CX=8 cm

OD=5 cm

Area of triangle=\frac{1}{2}\times base\times height

2

1

×base×height

Using the formula

Area of triangle ABC=\frac{1}{2}\times AB\times CX=\frac{1}{2}\times 8\times 25=100 cm^2

2

1

×AB×CX=

2

1

×8×25=100cm

2

Area of triangle BCD=\frac{1}{2}\times BC\times OD=\frac{1}{2}\times 16\times 5=40 cm^2

2

1

×BC×OD=

2

1

×16×5=40cm

2

Area of quadrilateral ABCD=Ar(ABC)+ar(BCD)=100+40=140 square cm

Hence, the area of quadrilateral ABCD=140 square cm

Answer 2

Answer:

Check your answer please