Question

in quadrilateral ABCD diadonal AC and BD BISECT point P .show that AP/PD=PC/BP

Answer 1

Answer:

Ooooooooooooooooooooooo

Answer 2

AP/PD=PC/BP

Step-by-step explanation:

point p bisect both diagonal, so AP=PC and BP=DP

here we similar triangle (APD and CPB) by SAS similarity criteria

then by property of similarity of triangle AP/CP=PD/PB

we cross change of PD and CP.

hence proved