Question

In quadrilateral ABCD, diagonal BD is perpendicular to sides AD and BC. The length of BD is 8. The length of side AB is 17 and the length of side CD is 10. What is the area of ABCD?​

Answer 1

Answer:

Area ABCD=84

Step-by-step explanation:

Area ABCD = Triangle ABD + Triangle BCD (Both are Right angled)

= 1/2*AD*BD+1/2*BC*BD

=1/2*BD*(AD+BC)

AD=$\sqrt(AB^2-BD^2)$=15

BC=$\sqrt(CD^2-BD^2)$=6

Thus, Area ABCD=1/2*8*(15+6)=84