Question

in quadrilateral ABCD,if angle A =80°, angle B=110° and angle angle C=50°.find. angle D....please help me​

Answer 1

Given :

In a quadrilateral :

• ∠A=80° , ∠B=110° and ∠C=50°

To find :

• ∠D.

Solution:

Let ∠ D = x .

As we know that in a quadrilateral :

${\boxed{\bf {Sum\:of\:angles=360^{\circ}}}}$

• Substitute the values

$:\leadsto\sf 80^{\circ}+110^{\circ}+50^{\circ}+x=360 ^{\circ}$

$:\leadsto \sf x+240^{\circ}=360^{\circ}$

$:\leadsto \sf x={(360-240)} ^{\circ}$

$:\leadsto {\underline{\boxed{\bf {x=120^{\circ}}}}}$

$\huge{\green{\therefore}}$ ∠D = 120°.