Question

IN Quadrilateral ABCD,<A+<B=150° then <C+<D=
​

Answer 1

Answer:

let the angle b,c,d be x,x,x

( As the three angles are equal )

now angle sum property of quadrilateral= 360 degree

given;

Angle A=150 degree

therefore,

angle AtangleB+angle C+angle D=360 degree

150+3x=360 degree

3x-210

x=70

hence,angles are 150,70,70 and 70 degrees

$\:$