In quadrilateral ABCD, P,Q,R,S are mid-point of sides AB,BC,CD,DA respectively then prove that quadrilateral ABCD is parallelogram
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Argument behind PQ=SR and PQ∥AC:-
In triangle ABC, P, Q are the mid points of the sides AB, BC.
So it follows that PQ= ½
AC ...(1) and PQ∥AC.
Similarly from triangle ACD it follows that SR= ½
AC ...(2) and SR∥AC.
From (1) and (2) we've,
PQ=SR.
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