In quadrilateral ABCD, side AB is parallel to side DC. A ZA : Z - 1:2 2C: 28 =4:5.
Calculato each angle of the quadrilateral.
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Answer:
∠A : ∠D = 1:2
Let ∠A = x and ∠B = 2x
∵ ∠C : ∠B = 4 : 5 Let ∠C = 4y and ∠B = 5y
∵ AB || DC
∠A + ∠D = 180° x + 2x = 180°
3x = 180° x = 60°
∴ A = 60°
∠D = 2x = 2 x 60 = 120° Again ∠B + ∠C = 180°
5y + 4y= 180°
9y = 180°
y = 20°
∴ ∠B = 5y- = 5 x 20 = 100°
∠C = 4y = 4 x 20 = 80°
Hence ∠A = 60° ; ∠B = 100° ; ∠C = 80° and ∠D = 120°
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