Question

In quadrilateral ABCD, side AB is parallel to side DC. If Angle A: Angle D = 1 : 2 and
Angle C: Angle B = 4:5.
calculate each angle.

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with proper method and fast response.​

Answer 1

Step-by-step explanation:

GIVEN

ABCD is a quadrilateral

AB||DC , angle A:angleD=1:2

Angle C:AngleB=4:5

therefore angle A= X

angle D=2x

angleCl C=4x

angle B=5x

the sum of interior angle of quadrilateral is 360degree

therefore

Angle A+ Angle But+Angle C+ Angle D=360°

X+5X+4X+2X=360°

12X=369°

Therefore X= 30°

Angle A= X=30°

Angle B=5X=5 ×30°= 150°

Angle C= 4X= 4× 30= 120°

Angle D= 2X = 2×30°=60°