Math, asked by Nithishmahi, 1 year ago

In quadrilateral ABCD, the bisector of angleC &angleD intersect at O. Prove that angleCOD=1/2(angleA+angleB)

Nithishmahi: Ya

Abhishek111111111uw: Hi

Nithishmahi: Plz answer

Abhishek111111111uw: It indicate the detailed step

Abhishek111111111uw: Ok

Abhishek111111111uw: If you want to write

Abhishek111111111uw: you can write

Nithishmahi: More I can't understand plz iam poor in maths

Nithishmahi: Understand my problem and help me

Mather: hey! he just convert ag. C and ag.D into ag.A and ag.B to obtain the required realation

Answers

Answered by Abhishek111111111uw

Hi see this answer If you have any doubt remind me

Attachments:

Nithishmahi: What that arrows indicate bro in the problem

Abhishek111111111uw: It indicates the detailed step

Nithishmahi: Can u again plz explain me in detail

Nithishmahi: Plz

Abhishek111111111uw: Ok wait i will send from the detailed step

Nithishmahi: Ok

Answered by rajesh195

Given that
in a quadrilateral ABCD,the bisector of angle C and angleD intersect at O
angleA=angleC (hence opposite angles of a quadrilateral are equal)
angleB=angleD (opposite angles are equal)
therefore angleCOD=1/2(angleC+D)
we know that angleA=angleC and angleB=angleD
therefore angleCOD=1/2of(angleA+angleB) hence proved

Nithishmahi: Tq bro

Previous Question

Next Question