Question

In quadrilateral ABCD, ZB = ZD = 90°,
AB = 7 cm, AC = 25 cm, CD = 20 cm.
Find the area of ABCD.​

Answer 1

Answer:

234 sq cm

Step-by-step explanation:

252 = 72 + BC2

BC2 =625 - 49 = 576 sq cm

BC = 24 cm

Area of ABC is (1/2)*AB*BC = (1/2)*7*24 sq cm = 84 sq cm

Area of ABCD is area of ABC + DBC = 84  +  150 sq cm = 234 sq cm

Answer 2

Answer:

How could be side ZB equal to angel 90